(Total Commander) How to open the parent folder of folder/zip/rar if open path?

[jogw]

I have set "Open path":

Code: Select all

$exec("c:\totalcmd\TOTALCMD64.EXE" /O /T /L="%1") 

It's good.When I "Open path" the file "d:\ht\1.jpg", tc will open "d:\ht\"

but to a folder, TC will open the folder. If zip/rar, TC will open the zip/rar file.

zip file: "d:\ht\2.zip", tc will open "d:\ht\2.zip\" with its packer, not"d:\ht\"
rar file: "d:\ht\3.rar", tc will open "d:\ht\2.rar\" with its packer, not"d:\ht\"
folder: "d:\ht\4\", tc will directly open "d:\ht\4\", not the parent foler "d:\ht\"



How to open the parent folder?

Any answer will help.

[tuska]

I have this command under "Open path":

Code: Select all

$exec("c:\totalcmd\TOTALCMD64.EXE" /o /A /S "%1")

/A When an archive file is passed as path, do not open it, but instead open the directory containing the archive
and set the archive as the active file (place the text cursor on it)

Please see: TC-Help (F1), 4.a. Command line parameters

[jogw]

Code: Select all

$exec("c:\totalcmd\TOTALCMD64.EXE" /o /A /S "%1")

it works well. Thanks a lot

but how to open the parent folder of a folder?

[tuska]

Everything Options - Context Menu - Explore Path

Code: Select all

$exec("c:\totalcmd\TOTALCMD64.EXE" /o /S $parent("%1"))

Right-click on the folder - Explore Path.

[jogw]

Thanks.Finally I can use tc, replace explorer.